उन तालिकाओं को देखें जिनमें टेबल में किसी निश्चित कॉलम के लिए विदेशी कुंजी हैं?

Question

क्या यह संभव है? यदि हां, तो देखने के लिए टेबल, कहीं भी शामिल हैं।

Answer 1

कुछ इस तरह की कोशिश करो

select uc.table_name 
from sys.user_cons_columns ucc 
join sys.user_constraints uc 
on uc.r_constraint_name = ucc.constraint_name 
where constraint_type = 'R' 
and ucc.table_name = :1 
and ucc.column_name = :2 

जहां

:1 = referenced table 
:2 = referenced column 

Answer 2

select * from user_constraints where r_constraint_name =<PK_NAME> 

जहां <PK_NAME> स्तंभ के प्राथमिक कुंजी बाधा का नाम है

Answer 3

दो उम्मीदवार प्रश्नों कि यहाँ मदद कर सकता है कर रहे हैं:

http://www.alberton.info/oracle_meta_info.html

SELECT alc.constraint_name, 
      CASE alc.constraint_type 
      WHEN 'P' THEN 'PRIMARY KEY' 
      WHEN 'R' THEN 'FOREIGN KEY' 
      WHEN 'U' THEN 'UNIQUE' 
      WHEN 'C' THEN 'CHECK' 
      END "constraint_type", 
      alc.DELETE_RULE "on_delete", 
      CASE alc.deferrable WHEN 'NOT DEFERRABLE' THEN 0 ELSE 1 END "deferrable", 
      CASE alc.deferred WHEN 'IMMEDIATE' THEN 1 ELSE 0 END "initially_deferred", 
      alc.search_condition, 
      alc.table_name, 
      cols.column_name, 
      cols.position, 
      r_alc.table_name "references_table", 
      r_cols.column_name "references_field", 
      r_cols.position "references_field_position" 
    FROM all_cons_columns cols 
LEFT JOIN all_constraints alc 
     ON alc.constraint_name = cols.constraint_name 
     AND alc.owner = cols.owner 
LEFT JOIN all_constraints r_alc 
     ON alc.r_constraint_name = r_alc.constraint_name 
     AND alc.r_owner = r_alc.owner 
LEFT JOIN all_cons_columns r_cols 
     ON r_alc.constraint_name = r_cols.constraint_name 
     AND r_alc.owner = r_cols.owner 
     AND cols.position = r_cols.position 
    WHERE alc.constraint_name = cols.constraint_name 
     AND alc.constraint_name = 'TESTCONSTRAINTS_ID_FK' 
     AND alc.table_name = 'TESTCONSTRAINTS2';