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मैं वसंत, हाइबरनेट, स्ट्रूट्स और मेवेन का उपयोग कर वेब एप्लिकेशन बना रहा हूं।स्वाभाविक निर्भरताओं का इंजेक्शन विफल रहा; नेस्टेड अपवाद है org.springframework.beans.factory.BeanCreationException:
import com.opensymphony.xwork2.Action;
import org.project.model.User;
import org.proejct.service.UserManager;
import org.junit.Test;
import org.springframework.beans.factory.annotation.Autowired;
import org.subethamail.wiser.Wiser;
import static org.junit.Assert.*;
public class PasswordHintActionTest extends BaseActionTestCase {
@Autowired
private PasswordHintAction action;
@Autowired
private UserManager userManager;
@Test
public void testExecute() throws Exception {
// start SMTP Server
Wiser wiser = new Wiser();
wiser.setPort(getSmtpPort());
wiser.start();
action.setUsername("user");
assertEquals("success", action.execute());
assertFalse(action.hasActionErrors());
// verify an account information e-mail was sent
wiser.stop();
assertTrue(wiser.getMessages().size() == 1);
// verify that success messages are in the request
assertNotNull(action.getSession().getAttribute("messages"));
}
}
मेरे applicationcontext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd"
default-lazy-init="true">
<!-- Activates scanning of @Autowired -->
<context:annotation-config/>
<!-- Activates scanning of @Repository and @Service -->
<context:component-scan base-package="com.project"/>
<!-- Compass Search Section -->
<!-- Compass Bean, automatically scanning for searchable classes within the model -->
<!-- Hooks into Spring transaction management and stores the index on the file system -->
<bean id="compass" class="org.compass.spring.LocalCompassBean">
<property name="mappingScan" value="org.project"/>
<property name="postProcessor" ref="compassPostProcessor"/>
<property name="transactionManager" ref="transactionManager" />
<property name="settings">
<map>
<entry key="compass.engine.connection" value="target/test-index" />
</map>
</property>
</bean>
मैं:
org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'com.project.action.PasswordHintActionTest': Injection of autowired dependencies failed; nested exception is org.springframework.beans.factory.BeanCreationException: Could not autowire field: private com.project.action.PasswordHintAction com.project.action.PasswordHintActionTest.action; nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException: No matching bean of type [com.project.action.PasswordHintAction] found for dependency: expected at least 1 bean which qualifies as autowire candidate for this dependency. Dependency annotations: {@org.springframework.beans.factory.annotation.Autowired(required=true)}
निम्नलिखित वर्ग Autowired निर्भरता है कि है:
जब मैं mvn clean install आदेश चला मैं नीचे त्रुटि मिलती है Autowired निर्भर स्कैन करने के लिए मेरे संदर्भ विन्यास में जोड़ा है encies। लेकिन मुझे यकीन नहीं है कि यह अभी भी यह अपवाद क्यों दे रहा है।
मैं भी निम्नलिखित तरीके से इसे जोड़ने की कोशिश की लेकिन मैं अभी भी एक ही अपवाद
<context:component-scan base-package="com.project.*"/>
अद्यतन प्राप्त करें:
निम्नलिखित पासवर्ड संकेत कार्रवाई है
import org.project.model.User;
import com.project.webapp.util.RequestUtil;
import org.springframework.mail.MailException;
import org.springframework.security.core.userdetails.UsernameNotFoundException;
import java.util.ArrayList;
import java.util.List;
public class PasswordHintAction extends BaseAction {
private static final long serialVersionUID = -4037514607101222025L;
private String username;
/**
* @param username The username to set.
*/
public void setUsername(String username) {
this.username = username;
}
/**
* Execute sending the password hint via e-mail.
*
* @return success if username works, input if not
*/
public String execute() {
List<Object> args = new ArrayList<Object>();
// ensure that the username has been sent
if (username == null) {
log.warn("Username not specified, notifying user that it's a required field.");
args.add(getText("user.username"));
addActionError(getText("errors.requiredField", args));
return INPUT;
}
if (log.isDebugEnabled()) {
log.debug("Processing Password Hint...");
}
// look up the user's information
try {
User user = userManager.getUserByUsername(username);
String hint = user.getPasswordHint();
if (hint == null || hint.trim().equals("")) {
log.warn("User '" + username + "' found, but no password hint exists.");
addActionError(getText("login.passwordHint.missing"));
return INPUT;
}
StringBuffer msg = new StringBuffer();
msg.append("Your password hint is: ").append(hint);
msg.append("\n\nLogin at: ").append(RequestUtil.getAppURL(getRequest()));
mailMessage.setTo(user.getEmail());
String subject = '[' + getText("webapp.name") + "] " + getText("user.passwordHint");
mailMessage.setSubject(subject);
mailMessage.setText(msg.toString());
mailEngine.send(mailMessage);
args.add(username);
args.add(user.getEmail());
saveMessage(getText("login.passwordHint.sent", args));
} catch (UsernameNotFoundException e) {
log.warn(e.getMessage());
args.add(username);
addActionError(getText("login.passwordHint.error", args));
getSession().setAttribute("errors", getActionErrors());
return INPUT;
} catch (MailException me) {
addActionError(me.getCause().getLocalizedMessage());
getSession().setAttribute("errors", getActionErrors());
return INPUT;
}
return SUCCESS;
}
}
अद्यतन 2:
applicationContext-struts.xml:
<bean id="passwordHintAction" class="com.project.action.PasswordHintAction" scope="prototype">
<property name="userManager" ref="userManager"/>
<property name="mailEngine" ref="mailEngine"/>
<property name="mailMessage" ref="mailMessage"/>
</bean>
मैं केवल अपने संदर्भ फ़ाइल का एक हिस्सा है, जो प्रकार PasswordHintAction के किसी भी सेम शामिल नहीं है देखना –
@Kltis: संपादित उत्तर –
@Klits: मैंने अपना जवाब संपादित किया, एक नज़र डालें। –