दिखाएँ एसक्यूएल परिणाम

Question

सभी मैं चाहता हूँ इस को बदलने के लिए है

Department | 201601 Print | 201601 Copy | 201602 Print | 201602 Copy | 201603 Print | 201603 Copy 
------------------------------------------------------------------------------------------ 
Dept 1  | 10   | 20   | 30   | 40   | 50   | 60 
Dept 2  | 20   | 10   | 40   | 30   | 60   | 50 

मैं PIVOT साथ स्क्रिप्ट का निर्माण करने की कोशिश कर रहा था, लेकिन मैं पता नहीं कैसे कॉलम में प्रत्येक अवधि के "प्रिंट" और "कॉपी" दोनों को दिखाने के लिए। इसके अलावा, चूंकि 'अवधि' के मान अज्ञात होंगे इसलिए मैं स्क्रिप्ट में मूल्य को हार्ड-कोड भी नहीं कर सकता।

SELECT [Department] 
    ,[201601] AS [201601 Copy] 
    ,[201602] AS [201602 Copy] 
    ,[201603] AS [201603 Copy] 
FROM 
    (SELECT [Copy], [Period], [Department] from #tempTable) AS ST 
PIVOT 
    (SUM([Copy]) FOR [Period] IN ([201601],[201602],[201603])) AS PT 

और यहाँ मेरे नमूना डेटा के साथ तालिका बनाने के लिए स्क्रिप्ट है:

IF OBJECT_ID('tempdb..#tempTable') IS NOT NULL 
    DROP TABLE #tempTable 
CREATE TABLE #tempTable(
    [Period] varchar(50) 
    ,[Department] varchar(50) 
    ,[Print] int 
    ,[Copy] int 
) 
INSERT INTO #tempTable VALUES 
    ('201601', 'Dept 1', 10, 20) 
    ,('201601', 'Dept 2', 20, 10) 
    ,('201602', 'Dept 1', 30, 40) 
    ,('201602', 'Dept 2', 40, 30) 
    ,('201603', 'Dept 1', 50, 60) 
    ,('201603', 'Dept 2', 60, 50) 

पहले से कोई उत्तर के लिए धन्यवाद

यहाँ मेरी प्रयास है।

उत्तर

मुझे प्राप्त जवाब का अध्ययन किया और अंत में नीचे स्क्रिप्ट का निर्माण:

DECLARE @sql AS varchar(max); 
SELECT @sql = 'SELECT [Department],' + 
    STUFF((
     SELECT DISTINCT 
      ',SUM(ISNULL(CASE [Period] WHEN ''' + [Period] + ''' THEN [Print] END, 0)) AS [' + [period] + ' Print]' + 
      ',SUM(ISNULL(CASE [Period] WHEN ''' + [Period] + ''' THEN [Copy] END, 0)) AS [' + [period] + ' Copy]' 
     FROM #TempTable 
     FOR XML PATH('') 
    ), 1, 1, '') + 
    'FROM #TempTable 
    GROUP BY [Department]'; 
PRINT @sql 
EXEC(@sql); 

Answer 1

आप एक गतिशील एसक्यूएल क्वेरी का उपयोग कर सकते हैं।

क्वेरी

declare @sql as varchar(max); 
select @sql = 'select [Department],' + stuff((
    select distinct ',max(case [Period] when ' + char(39) + [Period] + char(39) + 
    ' then [Print] end) [' + [period] + ' Print]' 
    + ',max(case [Period] when ' + char(39) + [Period] + char(39) + 
    ' then [Copy] end) [' + [period] + ' Copy]' 
    from #TempTable 
    for xml path('') 
), 1, 1, ''); 

select @sql += ' from #TempTable group by [Department];'; 
exec(@sql); 

Answer 2

आप इस IsNull का उपयोग कर() और SUM() कार्य को प्राप्त कर सकते हैं।

SELECT [Department] 
     ,SUM(ISNULL(CASE WHEN [Period]='201601' THEN [Print] END,0)) AS [201601 Print] 
     ,SUM(ISNULL(CASE WHEN [Period]='201601' THEN Copy END,0)) AS [201601 Copy] 
     ,SUM(ISNULL(CASE WHEN [Period]='201602' THEN [Print] END,0)) AS [201602 Print] 
     ,SUM(ISNULL(CASE WHEN [Period]='201602' THEN Copy END,0)) AS [201602 Copy] 
     ,SUM(ISNULL(CASE WHEN [Period]='201603' THEN [Print] END,0)) AS [201603 Print] 
     ,SUM(ISNULL(CASE WHEN [Period]='201603' THEN Copy END,0)) AS [201603 Copy]    
FROM #tempTable 
GROUP BY [Department] 

Answer 3

SELECT Department,SUM([201601Print])[201601 Print],SUM([201601Copy])[201601 Copy],SUM([201602Print])[201602 Print], 
       SUM([201602Copy])[201602 Copy],SUM([201603Print])[201603 Print],SUM([201603Copy])[201603 Copy] FROM (
SELECT [Department] 
,[201601] AS [201601Copy] 
,[201602] AS [201602Copy] 
,[201603] AS [201603Copy] 
,0 AS [201601Print] 
,0 AS [201602Print] 
,0 AS [201603Print] 
FROM 
(SELECT [Period],[Copy], [Department] from #tempTable) AS ST 
PIVOT 
(SUM([Copy]) FOR [Period] IN ([201601],[201602],[201603])) AS PT 
UNION ALL 
SELECT [Department] 
,0 AS [201601Copy] 
,0 AS [201602Copy] 
,0 AS [201603Copy] 
,[201601] AS [201601Print] 
,[201602] AS [201602Print] 
,[201603] AS [201603Print] 
FROM 
(SELECT [Period],[Print], [Department] from #tempTable) AS ST 
PIVOT 
(SUM([Print]) FOR [Period] IN ([201601],[201602],[201603])) AS PT 
)A GROUP BY Department 

Answer 4

एक धुरी का उपयोग करता है एक और गतिशील एसक्यूएल।
लेकिन यह कॉलम नामों के साथ एक स्ट्रिंग उत्पन्न करने के लिए एक चर @ कॉलम का उपयोग करता है।

declare @Columns varchar(max); 
set @Columns = STUFF((SELECT ', ' + QUOTENAME([Period] +' Print') + ', ' + QUOTENAME([Period] +' Copy') FROM #tempTable GROUP BY [Period] FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(max)') ,1,1,''); 

declare @SQL varchar(max); 
set @SQL = 'select * 
from (
select [Department], [Period] + '' Print'' as Title, [Print] as Value from #tempTable 
union all 
select [Department], [Period] + '' Copy'' as Title, [Copy] as Value from #tempTable 
) q 
pivot (sum(Value) for Title in ('+ @Columns +')) p;'; 

--select @SQL; 
exec (@SQL);