निम्न क्वेरी 1.6 सेकंडयह WHERE क्लॉज मेरी क्वेरी 180 गुना धीमा क्यों करता है?
SET @num :=0, @current_shop_id := NULL, @current_product_id := NULL;
#this query limits the results of the query within it by row number (so that only 250 products get displayed per store)
SELECT * FROM (
#this query adds row numbers to the query within it
SELECT *, @num := IF(@current_shop_id = shop_id, IF(@current_product_id=product_id,@num,@num+1), 0) AS row_number, @current_shop_id := shop_id AS shop_dummy, @current_product_id := product_id AS product_dummy FROM (
SELECT shop, shops.shop_id AS
shop_id, p1.product_id AS
product_id
FROM products p1 LEFT JOIN #this LEFT JOIN gets the favorites count for each product
(
SELECT fav3.product_id AS product_id, SUM(CASE
WHEN fav3.current = 1 AND fav3.closeted = 1 THEN 1
WHEN fav3.current = 1 AND fav3.closeted = 0 THEN -1
ELSE 0
END) AS favorites_count
FROM favorites fav3
GROUP BY fav3.product_id
) AS fav4 ON p1.product_id=fav4.product_id
INNER JOIN sex ON sex.product_id=p1.product_id AND
sex.sex=0 AND
sex.date >= SUBDATE(NOW(),INTERVAL 1 DAY)
INNER JOIN shops ON shops.shop_id = p1.shop_id
ORDER BY shop, sex.DATE, product_id
) AS testtable
) AS rowed_results WHERE
rowed_results.row_number>=0 AND
rowed_results.row_number<(7)
अंतिम कहां खंड क्वेरी 292 सेकंड में निष्पादित करने के लिए कारण बनता है AND shops.shop_id=86
जोड़ने में कार्यान्वित: AND shops.shop_id=86
साथ
SET @num :=0, @current_shop_id := NULL, @current_product_id := NULL;
#this query limits the results of the query within it by row number (so that only 250 products get displayed per store)
SELECT * FROM (
#this query adds row numbers to the query within it
SELECT *, @num := IF(@current_shop_id = shop_id, IF(@current_product_id=product_id,@num,@num+1), 0) AS row_number, @current_shop_id := shop_id AS shop_dummy, @current_product_id := product_id AS product_dummy FROM (
SELECT shop, shops.shop_id AS
shop_id, p1.product_id AS
product_id
FROM products p1 LEFT JOIN #this LEFT JOIN gets the favorites count for each product
(
SELECT fav3.product_id AS product_id, SUM(CASE
WHEN fav3.current = 1 AND fav3.closeted = 1 THEN 1
WHEN fav3.current = 1 AND fav3.closeted = 0 THEN -1
ELSE 0
END) AS favorites_count
FROM favorites fav3
GROUP BY fav3.product_id
) AS fav4 ON p1.product_id=fav4.product_id
INNER JOIN sex ON sex.product_id=p1.product_id AND
sex.sex=0 AND
sex.date >= SUBDATE(NOW(),INTERVAL 1 DAY)
INNER JOIN shops ON shops.shop_id = p1.shop_id AND
shops.shop_id=86
ORDER BY shop, sex.DATE, product_id
) AS testtable
) AS rowed_results WHERE
rowed_results.row_number>=0 AND
rowed_results.row_number<(7)
मैं दुकानों तालिका सीमित सोचा होगा होगा निष्पादन समय को कम करें। इसके बजाए, निष्पादन समय उत्पादों की दुकानों में पंक्तियों की संख्या पर निर्भर करता है, विशेष दुकानों के समान products.shop_id के साथ .shop_id। Product.shop_id = 86 के साथ उत्पाद तालिका में लगभग 34K पंक्तियां हैं, और निष्पादन समय 2 9 2 सेकंड है। Products.shop_id = 50 के लिए, लगभग 28K पंक्तियां हैं, और निष्पादन समय 210 सेकंड है। Products.shop_id = 175 के लिए, लगभग 2K पंक्तियां हैं, और निष्पादन समय 2.8 सेकंड है। क्या हो रहा है?
1.6 दूसरी क्वेरी के लिए बढ़ाया समझाने है:
इस विस्तारित समझाने के लिएid select_type table type possible_keys key key_len ref rows filtered Extra
1 PRIMARY <derived2> ALL NULL NULL NULL NULL 1203 100.00 Using where
2 DERIVED <derived3> ALL NULL NULL NULL NULL 1203 100.00
3 DERIVED sex ALL product_id_2,product_id NULL NULL NULL 526846 75.00 Using where; Using temporary; Using filesort
3 DERIVED p1 eq_ref PRIMARY,shop_id,shop_id_2,product_id,shop_id_3 PRIMARY 4 mydatabase.sex.product_id 1 100.00
3 DERIVED <derived4> ALL NULL NULL NULL NULL 14752 100.00
3 DERIVED shops eq_ref PRIMARY PRIMARY 4 mydatabase.p1.shop_id 1 100.00
4 DERIVED fav3 ALL NULL NULL NULL NULL 15356 100.00 Using temporary; Using filesort
शो चेतावनी
-----+
| Note | 1003 | select `rowed_results`.`shop` AS `shop`,`rowed_results`.`shop_id` AS `shop_id`,`rowed_results`.`product_id` AS `product_id`,`rowed_results`.`row_number` AS `row_number`,`rowed_results`.`shop_dummy` AS `shop_dummy`,`rowed_results`.`product_dummy` AS `product_dummy` from (select `testtable`.`shop` AS `shop`,`testtable`.`shop_id` AS `shop_id`,`testtable`.`product_id` AS `product_id`,(@num:=if(((@current_shop_id) = `testtable`.`shop_id`),if(((@current_product_id) = `testtable`.`product_id`),(@num),((@num) + 1)),0)) AS `row_number`,(@current_shop_id:=`testtable`.`shop_id`) AS `shop_dummy`,(@current_product_id:=`testtable`.`product_id`) AS `product_dummy` from (select `mydatabase`.`shops`.`shop` AS `shop`,`mydatabase`.`shops`.`shop_id` AS `shop_id`,`mydatabase`.`p1`.`product_id` AS `product_id` from `mydatabase`.`products` `p1` left join (select `mydatabase`.`fav3`.`product_id` AS `product_id`,sum((case when ((`mydatabase`.`fav3`.`current` = 1) and (`mydatabase`.`fav3`.`closeted` = 1)) then 1 when ((`mydatabase`.`fav3`.`current` = 1) and (`mydatabase`.`fav3`.`closeted` = 0)) then -(1) else 0 end)) AS `favorites_count` from `mydatabase`.`favorites` `fav3` group by `mydatabase`.`fav3`.`product_id`) `fav4` on(((`mydatabase`.`p1`.`product_id` = `mydatabase`.`sex`.`product_id`) and (`fav4`.`product_id` = `mydatabase`.`sex`.`product_id`))) join `mydatabase`.`sex` join `mydatabase`.`shops` where ((`mydatabase`.`sex`.`sex` = 0) and (`mydatabase`.`p1`.`product_id` = `mydatabase`.`sex`.`product_id`) and (`mydatabase`.`shops`.`shop_id` = `mydatabase`.`p1`.`shop_id`) and (`mydatabase`.`sex`.`date` >= (now() - interval 1 day))) order by `mydatabase`.`shops`.`shop`,`mydatabase`.`sex`.`date`,`mydatabase`.`p1`.`product_id`) `testtable`) `rowed_results` where ((`rowed_results`.`row_number` >= 0) and (`rowed_results`.`row_number` < 7)) |
+------
292 दूसरी क्वेरी के लिए बढ़ाया समझाने जाता है:
id select_type table type possible_keys key key_len ref rows filtered Extra
1 PRIMARY <derived2> ALL NULL NULL NULL NULL 36 100.00 Using where
2 DERIVED <derived3> ALL NULL NULL NULL NULL 36 100.00
3 DERIVED shops const PRIMARY PRIMARY 4 1 100.00 Using temporary; Using filesort
3 DERIVED p1 ref PRIMARY,shop_id,shop_id_2,product_id,shop_id_3 shop_id 4 11799 100.00
3 DERIVED <derived4> ALL NULL NULL NULL NULL 14752 100.00
3 DERIVED sex eq_ref product_id_2,product_id product_id_2 5 mydatabase.p1.product_id 1 100.00 Using where
4 DERIVED fav3 ALL NULL NULL NULL NULL 15356 100.00 Using temporary; Using filesort
इस विस्तार के लिए चेतावनी दिखाएं
है----+
| Note | 1003 | select `rowed_results`.`shop` AS `shop`,`rowed_results`.`shop_id` AS `shop_id`,`rowed_results`.`product_id` AS `product_id`,`rowed_results`.`row_number` AS `row_number`,`rowed_results`.`shop_dummy` AS `shop_dummy`,`rowed_results`.`product_dummy` AS `product_dummy` from (select `testtable`.`shop` AS `shop`,`testtable`.`shop_id` AS `shop_id`,`testtable`.`product_id` AS `product_id`,(@num:=if(((@current_shop_id) = `testtable`.`shop_id`),if(((@current_product_id) = `testtable`.`product_id`),(@num),((@num) + 1)),0)) AS `row_number`,(@current_shop_id:=`testtable`.`shop_id`) AS `shop_dummy`,(@current_product_id:=`testtable`.`product_id`) AS `product_dummy` from (select 'shop.nordstrom.com' AS `shop`,'86' AS `shop_id`,`mydatabase`.`p1`.`product_id` AS `product_id` from `mydatabase`.`products` `p1` left join (select `mydatabase`.`fav3`.`product_id` AS `product_id`,sum((case when ((`mydatabase`.`fav3`.`current` = 1) and (`mydatabase`.`fav3`.`closeted` = 1)) then 1 when ((`mydatabase`.`fav3`.`current` = 1) and (`mydatabase`.`fav3`.`closeted` = 0)) then -(1) else 0 end)) AS `favorites_count` from `mydatabase`.`favorites` `fav3` group by `mydatabase`.`fav3`.`product_id`) `fav4` on(((`fav4`.`product_id` = `mydatabase`.`p1`.`product_id`) and (`mydatabase`.`sex`.`product_id` = `mydatabase`.`p1`.`product_id`))) join `mydatabase`.`sex` join `mydatabase`.`shops` where ((`mydatabase`.`sex`.`sex` = 0) and (`mydatabase`.`sex`.`product_id` = `mydatabase`.`p1`.`product_id`) and (`mydatabase`.`p1`.`shop_id` = 86) and (`mydatabase`.`sex`.`date` >= (now() - interval 1 day))) order by 'shop.nordstrom.com',`mydatabase`.`sex`.`date`,`mydatabase`.`p1`.`product_id`) `testtable`) `rowed_results` where ((`rowed_results`.`row_number` >= 0) and (`rowed_results`.`row_number` < 7)) |
+-----
मैं MySQL क्लाइंट संस्करण चला रहा हूं: 5.1.56। दुकान तालिका में दुकान_आईडी पर प्राथमिक सूचकांक है:
Action Keyname Type Unique Packed Column Cardinality Collation Null Comment
Edit Drop PRIMARY BTREE Yes No shop_id 163 A
मैंने दुकान तालिका का विश्लेषण किया है लेकिन इससे मदद नहीं मिली है।
मुझे लगता है कि अगर मैं LEFT JOIN
हटाता हूं तो निष्पादन समय में अंतर 0.12 सेकेंड बनाम 0.12 सेकेंड तक गिर जाता है।
सीज़ का समाधान, अर्थात् क्वेरी के 1.6-सेकंड संस्करण का उपयोग करने के लिए और बाहरी क्वेरी (नीचे के रूप में) rowed_results.shop_dummy=86
जोड़कर अप्रासंगिक परिणामों को हटाकर, 1.7 सेकंड में निष्पादित करता है। यह समस्या को हल करता है, लेकिन रहस्य बनी हुई है कि 2 9 2-दूसरी क्वेरी इतनी धीमी क्यों है।
SET @num :=0, @current_shop_id := NULL, @current_product_id := NULL;
#this query limits the results of the query within it by row number (so that only 250 products get displayed per store)
SELECT * FROM (
#this query adds row numbers to the query within it
SELECT *, @num := IF(@current_shop_id = shop_id, IF(@current_product_id=product_id,@num,@num+1), 0) AS row_number, @current_shop_id := shop_id AS shop_dummy, @current_product_id := product_id AS product_dummy FROM (
SELECT shop, shops.shop_id AS
shop_id, p1.product_id AS
product_id
FROM products p1 LEFT JOIN #this LEFT JOIN gets the favorites count for each product
(
SELECT fav3.product_id AS product_id, SUM(CASE
WHEN fav3.current = 1 AND fav3.closeted = 1 THEN 1
WHEN fav3.current = 1 AND fav3.closeted = 0 THEN -1
ELSE 0
END) AS favorites_count
FROM favorites fav3
GROUP BY fav3.product_id
) AS fav4 ON p1.product_id=fav4.product_id
INNER JOIN sex ON sex.product_id=p1.product_id AND sex.sex=0
INNER JOIN shops ON shops.shop_id = p1.shop_id
WHERE sex.date >= SUBDATE(NOW(),INTERVAL 1 DAY)
ORDER BY shop, sex.DATE, product_id
) AS testtable
) AS rowed_results WHERE
rowed_results.row_number>=0 AND
rowed_results.row_number<(7) AND
rowed_results.shop_dummy=86;
क्या है "को समझाने विस्तारित .." "दिखाएं चेतावनी" के बाद के उत्पादन में? –
Cez
... कथन के दोनों संस्करणों के लिए? अंतर क्या है यह देखने के लिए 'EXPLAIN' आउटपुट की तुलना करें। एक ही 'WHERE' खंड में सभी कॉलम एक कुंजी में जाना चाहिए। – feeela
@Cez @feela अनुस्मारक के लिए धन्यवाद, मैंने प्रश्न के लिए 'विस्तारित विस्तारित' प्रश्न जोड़े हैं। 'चेतावनी' ने कोई परिणाम नहीं दिया। – jela