यहां मुझे जो मिला है; यह एक उदाहरण है और इसे आपकी स्थिति में सामान्यीकृत या अनुकूलित किया जा सकता है।
CREATE TABLE IF NOT EXISTS `language_family_adj_list` (
`language_id` int(11) NOT NULL auto_increment,
`language` varchar(20) NOT NULL,
`parent_id` int(11) default NULL,
PRIMARY KEY (`language_id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=41 ;
INSERT INTO `language_family_adj_list` (`language_id`, `language`, `parent_id`) VALUES
(1, 'Finno-Ugric', NULL),
(2, 'Hungarian', 1),
(3, 'Khanty', 1),
(4, 'Mansi', 1),
(5, 'Permic', 1),
(6, 'Mari', 1),
(7, 'Mordvinic', 1),
(8, 'Sami', 1),
(9, 'Baltic-Finnic', 1),
(10, 'Komi', 5),
(11, 'Komi-Permyak', 5),
(12, 'Udmurt', 5),
(13, 'Erzya', 7),
(14, 'Moksha', 7),
(15, 'Western Sami', 8),
(16, 'Eastern Sami', 8),
(17, 'Southern Sami', 15),
(18, 'Umi Sami', 15),
(19, 'Lule Sami', 15),
(20, 'Pite Sami', 15),
(22, 'Northern Sami', 15),
(23, 'Kemi Sami', 16),
(24, 'Inari Sami', 16),
(25, 'Akkala Sami', 16),
(26, 'Kildin Sami', 16),
(27, 'Skolt Sami', 16),
(28, 'Ter Sami', 16),
(29, 'Estonian', 9),
(30, 'Finnish', 9),
(31, 'Ingrian', 9),
(32, 'Karelian', 9),
(33, 'Livonian', 9),
(34, 'Veps', 9),
(35, 'Votic', 9),
(36, 'South Estonian', 29),
(37, 'Voro', 36),
(38, 'Karelian Proper', 32),
(39, 'Lude', 32),
(40, 'Olonets Karelian', 32);
यहाँ एक प्रश्न प्रदर्शित करने के लिए है:
mysql> SELECT t1.language AS lev1, t2.language as lev2, t3.language as lev3, t4.language as lev4, t5.language AS lev5
-> FROM language_family_adj_list AS t1
-> LEFT JOIN language_family_adj_list AS t2 ON t2.parent_id = t1.language_id
-> LEFT JOIN language_family_adj_list AS t3 ON t3.parent_id = t2.language_id
-> LEFT JOIN language_family_adj_list AS t4 ON t4.parent_id = t3.language_id
-> LEFT JOIN language_family_adj_list AS t5 ON t5.parent_id = t4.language_id
-> WHERE t1.parent_id IS NULL
-> ORDER BY t1.language, t2.language, t3.language, t4.language, t5.language;
+-------------+---------------+--------------+------------------+------+
| lev1 | lev2 | lev3 | lev4 | lev5 |
+-------------+---------------+--------------+------------------+------+
| Finno-Ugric | Baltic-Finnic | Estonian | South Estonian | Voro |
| Finno-Ugric | Baltic-Finnic | Finnish | NULL | NULL |
| Finno-Ugric | Baltic-Finnic | Ingrian | NULL | NULL |
| Finno-Ugric | Baltic-Finnic | Karelian | Karelian Proper | NULL |
| Finno-Ugric | Baltic-Finnic | Karelian | Lude | NULL |
| Finno-Ugric | Baltic-Finnic | Karelian | Olonets Karelian | NULL |
| Finno-Ugric | Baltic-Finnic | Livonian | NULL | NULL |
| Finno-Ugric | Baltic-Finnic | Veps | NULL | NULL |
| Finno-Ugric | Baltic-Finnic | Votic | NULL | NULL |
| Finno-Ugric | Hungarian | NULL | NULL | NULL |
| Finno-Ugric | Khanty | NULL | NULL | NULL |
| Finno-Ugric | Mansi | NULL | NULL | NULL |
| Finno-Ugric | Mari | NULL | NULL | NULL |
| Finno-Ugric | Mordvinic | Erzya | NULL | NULL |
| Finno-Ugric | Mordvinic | Moksha | NULL | NULL |
| Finno-Ugric | Permic | Komi | NULL | NULL |
| Finno-Ugric | Permic | Komi-Permyak | NULL | NULL |
| Finno-Ugric | Permic | Udmurt | NULL | NULL |
| Finno-Ugric | Sami | Eastern Sami | Akkala Sami | NULL |
| Finno-Ugric | Sami | Eastern Sami | Inari Sami | NULL |
| Finno-Ugric | Sami | Eastern Sami | Kemi Sami | NULL |
| Finno-Ugric | Sami | Eastern Sami | Kildin Sami | NULL |
| Finno-Ugric | Sami | Eastern Sami | Skolt Sami | NULL |
| Finno-Ugric | Sami | Eastern Sami | Ter Sami | NULL |
| Finno-Ugric | Sami | Western Sami | Lule Sami | NULL |
| Finno-Ugric | Sami | Western Sami | Northern Sami | NULL |
| Finno-Ugric | Sami | Western Sami | Pite Sami | NULL |
| Finno-Ugric | Sami | Western Sami | Southern Sami | NULL |
| Finno-Ugric | Sami | Western Sami | Umi Sami | NULL |
+-------------+---------------+--------------+------------------+------+
29 rows in set (0.00 sec)
तो यहाँ संशोधित अग्रिम आदेश ट्रावर्सल पेड़ तालिका स्कीमा है
सबसे पहले मैं एक निकटता सूची (विकिपीडिया से भाषा परिवार डेटा) पर सेट कर देंगे :
CREATE TABLE language_family_mptt (
language VARCHAR(30) NOT NULL,
lft INT NOT NULL,
rgt INT NOT NULL
) COLLATE utf8;
और फिर दा को माइग्रेट करने के लिए रिकर्सिव संग्रहीत प्रक्रिया है टा:
mysql> SELECT CONCAT(REPEAT(' ', (COUNT(parent.language) - 1)), node.language) AS name FROM language_family_mptt AS node, language_family_mptt AS parent WHERE node.lft BETWEEN parent.lft AND parent.rgt GROUP BY node.language ORDER BY node.lft;
+---------------------------------+
| name |
+---------------------------------+
| Finno-Ugric |
| Baltic-Finnic |
| Estonian |
| South Estonian |
| Voro |
| Finnish |
| Ingrian |
| Karelian |
| Karelian Proper |
| Lude |
| Olonets Karelian |
| Livonian |
| Veps |
| Votic |
| Hungarian |
| Khanty |
| Mansi |
| Mari |
| Mordvinic |
| Erzya |
| Moksha |
| Permic |
| Komi |
| Komi-Permyak |
| Udmurt |
| Sami |
| Eastern Sami |
| Akkala Sami |
| Inari Sami |
| Kemi Sami |
| Kildin Sami |
| Skolt Sami |
| Ter Sami |
| Western Sami |
| Lule Sami |
| Northern Sami |
| Pite Sami |
| Southern Sami |
| Umi Sami |
+---------------------------------+
39 rows in set (0.00 sec)
:
TRUNCATE TABLE language_family_mptt;
SET max_sp_recursion_depth = 255;
DROP PROCEDURE IF EXISTS insert_branches;
DROP PROCEDURE IF EXISTS start_tree;
DELIMITER ~~
CREATE PROCEDURE start_tree()
BEGIN
DECLARE language_field VARCHAR(100);
DECLARE done INT DEFAULT 0;
DECLARE insert_id INT;
DECLARE source_id INT;
DECLARE cursor1 CURSOR FOR SELECT language, language_id FROM language_family_adj_list WHERE parent_id IS NULL ORDER BY language;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1;
OPEN cursor1;
read_loop: LOOP
SET @my_left = 1;
FETCH cursor1 INTO language_field, source_id;
INSERT INTO language_family_mptt (language, lft) VALUES (language_field, 1);
CALL insert_branches(source_id);
UPDATE language_family_mptt SET rgt = @my_left + 1 WHERE lft = 1 AND rgt = 0;
IF done THEN
LEAVE read_loop;
END IF;
END LOOP;
CLOSE cursor1;
END; ~~
CREATE PROCEDURE insert_branches(IN source_parent_id INT)
BEGIN
DECLARE done INT DEFAULT 0;
DECLARE next_source_parent_id INT DEFAULT NULL;
DECLARE orig_left INT DEFAULT NULL;
DECLARE language_field VARCHAR(100);
DECLARE cursor1 CURSOR FOR SELECT language_id, language FROM language_family_adj_list WHERE parent_id = source_parent_id ORDER BY language;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1;
OPEN cursor1;
read_loop: LOOP
FETCH cursor1 INTO next_source_parent_id, language_field;
IF done THEN
LEAVE read_loop;
END IF;
SET @my_left = @my_left + 1;
INSERT INTO language_family_mptt (language, lft) VALUES (language_field, @my_left);
SET orig_left = @my_left;
CALL insert_branches(next_source_parent_id);
UPDATE language_family_mptt SET rgt = @my_left + 1 WHERE lft = orig_left AND rgt = 0 ;
SET @my_left = @my_left + 1;
END LOOP;
CLOSE cursor1;
END; ~~
DELIMITER ;
और यहाँ परिणाम है डी
क्या आप है पदानुक्रमिक स्तरों के एक ज्ञात संख्या - यह एक स्थिर डेटा सेट है, या उस पर काम करने की जरूरत है 'कोई भी' डेटा सेट? –
डेटा सेट में मैं काम कर रहा हूं, यह कम या ज्यादा स्थिर है, इसलिए ज्ञात स्तर हैं। – user151841
लेकिन मैं वास्तव में एक सामान्य उद्देश्य एल्गोरिदम की तलाश में हूं। – user151841