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मेरे पास एक ही आदेश के बारे में जानकारी एकत्र करने के लिए यह प्रश्न है और यह काफी जटिल हो गया है।MySQL क्या इनरजॉइन की कोई सीमा है?
मेरे पास परीक्षण करने के लिए कोई डेटा नहीं है इसलिए मैं पूछ रहा हूं, अगर किसी के पास छोटे और बड़े डेटा सेट में इसका अनुभव है, तो क्या एक सीमा में आप कितने जुड़ सकते हैं या बनाना चाहिए ? क्या बड़े प्रश्नों को छोटे हिस्सों में विभाजित करने की सलाह दी जाएगी या इससे कोई महत्वपूर्ण अंतर नहीं आएगा?
साथ ही, क्या INNER JOIN के बाद WHERE खंड होना वैध है?
आपकी सलाह के लिए धन्यवाद।
# Order: Get Order
function getOrder($order_id) {
$sql = "SELECT (order.id, order.created, o_status.status,
/* payment info */
order.total, p_status.status,
/* ordered by */
cust_title.title, cust.forename, cust.surname,
customer.phone, customer.email,
cust.door_name, cust.street1,
cust.street2, cust.town,
cust.city, cust.postcode,
/* deliver to */
recip_title.title, recipient.forename, recipient.surname,
recipient.door_name, recipient.street1,
recipient.street2, recipient.town,
recipient.city, recipient.postcode,
/* deliver info */
shipping.name, order.memo,
/* meta data */
order.last_update)
FROM tbl_order AS order
INNER JOIN tbl_order_st AS o_status
ON order.order_status_id = o_status.id
INNER JOIN tbl_payment_st AS p_status
ON order.payment_status_id = p_status.id
INNER JOIN (SELECT (cust_title.title, cust.forename, cust.surname,
customer.phone, customer.email,
/* ordered by */ cust.door_name, cust.street1,
cust.street2, cust.town,
cust.city, cust.postcode)
FROM tbl_customer AS customer
INNER JOIN tbl_contact AS cust
ON customer.contact_id = cust.id
INNER JOIN tbl_contact_title AS cust_title
ON cust.contact_title_id = cust_title.id
WHERE order.customer_id = customer.id)
ON order.customer_id = customer.id
INNER JOIN (SELECT (recip_title.title, recipient.forename, recipient.surname,
/* deliver to */ recipient.door_name, recipient.street1,
recipient.street2, recipient.town,
recipient.city, recipient.postcode)
FROM tbl_contact AS recipient
INNER JOIN tbl_contact_title AS recip_title
ON recipient.contact_title_id = recip_title.id
WHERE order.contact_id = recipient.id)
ON order.contact_id = recipient.id
INNER JOIN tbl_shipping_opt AS shipping
ON order.shipping_option_id = shipping.id
WHERE order.id = '?';";
dbQuery($sql, array((int)$order_id));
$rows = dbRowsAffected();
if ($rows == 1)
return dbFetchAll();
else
return null;
}
के बाद से किसी को इस प्रश्न के लिए स्कीमा का अनुरोध किया, यहाँ यह है:
# TBL_CONTACT_TITLE
DROP TABLE IF EXISTS tbl_contact_title;
CREATE TABLE tbl_contact_title(
id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id),
title CHAR(3)
) ENGINE = InnoDB;
INSERT INTO tbl_contact_title
(title)
VALUES ('MR'),
('MRS'),
('MS');
# TBL_CONTACT
DROP TABLE IF EXISTS tbl_contact;
CREATE TABLE tbl_contact(
id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id),
contact_title_id INT,
FOREIGN KEY(contact_title_id) REFERENCES tbl_contact_title(id) ON DELETE SET NULL,
forename VARCHAR(50),
surname VARCHAR(50),
door_name VARCHAR(25),
street1 VARCHAR(40),
street2 VARCHAR(40),
town VARCHAR(40),
city VARCHAR(40),
postcode VARCHAR(10),
currency_id INT,
FOREIGN KEY(currency_id) REFERENCES tbl_currency(id) ON DELETE SET NULL
) ENGINE = InnoDB;
# TBL_CUSTOMER
DROP TABLE IF EXISTS tbl_customer;
CREATE TABLE tbl_customer(
id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id),
contact_id INT,
FOREIGN KEY(contact_id) REFERENCES tbl_contact(id) ON DELETE SET NULL,
birthday DATE,
is_male TINYINT,
phone VARCHAR(20),
email VARCHAR(50) NOT NULL
) ENGINE = InnoDB, AUTO_INCREMENT = 1000;
# TBL_ORDER_ST
DROP TABLE IF EXISTS tbl_order_st;
CREATE TABLE tbl_order_st(
id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id),
status VARCHAR(25)
) ENGINE = InnoDB;
INSERT INTO tbl_order_st
(status)
VALUES
('NEW'),
('PROCESSING'),
('SHIPPED'),
('COMPLETED'),
('CANCELLED');
# TBL_SHIPPING_OPT
DROP TABLE IF EXISTS tbl_shipping_opt;
CREATE TABLE tbl_shipping_opt(
id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id),
name VARCHAR(50),
description VARCHAR(255),
cost DECIMAL(6,3)
) ENGINE = InnoDB;
INSERT INTO tbl_shipping_opt
(name, description, cost)
VALUES
('UK Premier', 'U.K. Mainland upto 30KG, Next Working Day', 8.00),
('Europe Standard', 'Most European Destinations* upto 30KG, 2 to 5 Working Days *please check before purchase', 15.00);
# TBL_PAYMENT_ST
DROP TABLE IF EXISTS tbl_payment_st;
CREATE TABLE tbl_payment_st(
id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id),
status VARCHAR(25)
) ENGINE = InnoDB;
INSERT INTO tbl_payment_st
(status)
VALUES
('UNPAID'),
('PAID');
# TBL_ORDER
DROP TABLE IF EXISTS tbl_order;
CREATE TABLE tbl_order(
id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id),
customer_id INT,
FOREIGN KEY(customer_id) REFERENCES tbl_customer(id) ON DELETE SET NULL,
contact_id INT,
FOREIGN KEY(contact_id) REFERENCES tbl_contact(id) ON DELETE SET NULL,
created DATETIME,
last_update TIMESTAMP,
memo VARCHAR(255),
order_status_id INT,
FOREIGN KEY(order_status_id) REFERENCES tbl_order_st(id),
shipping_option_id INT,
FOREIGN KEY(shipping_option_id) REFERENCES tbl_shipping_opt(id),
coupon_id INT,
FOREIGN KEY(coupon_id) REFERENCES tbl_coupon(id) ON DELETE SET NULL,
total DECIMAL(9,3),
payment_status_id INT,
FOREIGN KEY(payment_status_id) REFERENCES tbl_payment_st(id)
) ENGINE = InnoDB, AUTO_INCREMENT = 1000;
इसे अधिकतम तक दबाएं। जब तक आपको कोई वाक्यविन्यास त्रुटियां या "बहुत अधिक शामिल" जैसी कोई चीज़ नहीं मिलती, तब तक आगे बढ़ें। – hakre
@ हकर धन्यवाद ... मैं इसे तब लेता हूं, क्वेरी का आकार कोई फर्क नहीं पड़ता। – Ozzy